Cobalt reacts with excess aqueous hydrochloric acid to produce hydrogen. (a) Write a balanced chemical equation for the reaction, using the smallest integer coefficients possible. Write states in brackets. (Hint: CoCl2 is the second product.) Co + 2HCl --> 2H + CoCl2 (Is this formula correct?) (b) Calculate the mass of pure Co that will furnish 22.9 L of hydrogen at a pressure of 0.785 atm and a temperature of 27.6°C. = g
a) balanced chemical reaction between cobalt and HCl is given bellow
ans Co(s) +
2HCl(g)
H2(g) + CoCl2(s)
b) volume of H2 gas produced = 22.9 liter , pressure = 0.785 atm , temperature = 27.60 C
use ideal gas equation to find no of moles of H2 gas produced
Ideal gas equation
PV = nRT where, P = atm pressure= 0.785 atm,
V = volume in Liter = 22.9 L
n = number of mole = ?
R = 0.08205L atm mol-1 K-1 =Proportionality constant = gas constant,
T = Temperature in K = 27.60C = 273.15+ 27.6= 300.75 K
We can write ideal gas equation
n = PV/RT
Substitute the value
n = (0.785
22.9)/(0.08205
300.75) =
0.728 moles
0.728 moles of H2 gas are produced
according to balanced chemical equation given in part a for production of 1 mole of hydrogen gas requires 1 mole cobalt therefore for production of of 0.728 moles of hydrogen gas will require 0.728 mole of cobalt
no of moles of Co required = 0.728 moles , molar mass of Co = 58.93 gram/mole
mass in gram = no of moles x molar mass , substitute values to find grams of cobalt required
mass of cobalt required = 0.728 x 58.93 = 42.9 gram
ans 42.9 gram of pure cobalt will furnish 22.9 liter of hydrogen gas at 0.785 atm pressure and 27.60 C temperature
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