Question

Michael, a hamster lover, keeps his four pet hamster's in a roomy cage, where they spend much of their spare time–when they're not sleeping or eating–joyfully scampering about on the cage's floor. Michael tracks his hamster's health diligently and just now recorded their masses as 0.0211 kg, 0.0163 kg, 0.0247 kg, and 0.0167 kg. At this very instant the x and y components of the hamster's velocities are, respectively, (0.957 m/s, -0.513 m/s), (-0.827 m/s, -0.873 m/s), (0.233 m/s, 0.311 m/s), and (-0.101 m/s, 0.427 m/s). Calculate the x and y components of Michael's hamster's total momentum, p_x and p_y.

p_x = ____ kg m/s

p_y = ____ kg m/s

Answer 1

m₁= 0.0211 kg, m₂= 0.0163 kg, m₃ =0.0247 kg, m₄= 0.0167 kg

v₁= (0.957 m/s, -0.513 m/s), v₂= (-0.827 m/s, -0.873 m/s), v₃= (0.233 m/s, 0.311 m/s), v₄=(-0.101 m/s, 0.427 m/s)

P_x = P_1x + P_2x +P_3x +P_4x = m₁v_1x + m₂v_2x + m₃v_3x + m₄v_4x

P_x = (0.0211kg*0.957m/s) + (0.0163 kg*-0.827m/s) +(0.0247kg*0.233 m/s) +(0.0167kg*-0.101 m/s)

P_x = 0.0108 kg*m/s

P_y = P_1y + P_2y +P_3y +P_4y = m₁v_1y + m₂v_2y + m₃v_3y + m₄v_4y

P_y = (0.0211kg*-0.513 m/s) + (0.0163 kg*-0.873m/s) +(0.0247kg*0.311 m/s) +(0.0167kg*0.427 m/s)

P_y = -0.0103 kg*m/s