Suppose a hospital would like to estimate the proportion of patients who feel that physicians who care for them always communicated effectively when discussing their medical care. A pilot sample of 100 patients found that 70 reported that their physician communicated effectively. Determine the additional number of patients that need to be sampled to construct a 90% confidence interval with a margin of error equal to 1% to estimate this proportion.
Answer: The additional number of patients that need to be sampled is 5,582.
Above are the questions and answers. Please provide all Excel formulas (not calculations) that get to these answers.
| here margin of error E = | 0.01 | |
| for90% CI crtiical Z = | 1.645 # (from normsinv(0.95) function) | |
| estimated prop.=p=70/100= | 0.700 | |
| reqd. sample size n=p*(1-p)*(z/E)2=0.7*0.3*(1.645/0.01)^2 = | 5683.00 |
therefore additional number of patients that need to be sampled is =5683-100 =5583
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