Question

print a 3x3 magic square where each row and column add up to 15, but instead of numbers it must output roman numerals.

c++

Answer 1

#include <bits/stdc++.h>
using namespace std;
string roman(int x)
{
if(x==1)
return "I";
else if(x==2)
return "II";
else if(x==3)
return "III";
else if(x==4)
return "IV";
else if(x==5)
return "V";
else if(x==6)
return "VI";
else if(x==7)
return "VII";
else if(x==8)
return "VIII";
else if(x==9)
return "IX";
}
  
// A function to generate odd sized magic squares
void generateSquare(int n)
{
int magicSquare[n][n];
  

memset(magicSquare, 0, sizeof(magicSquare));
  
int i = n/2;
int j = n-1;
  

for (int num = 1; num <= n*n; )
{
if (i == -1 && j == n)
{
j = n-2;
i = 0;
}
else
{

if (j == n)
j = 0;
  
  
if (i < 0)
i = n - 1;
}
if (magicSquare[i][j])
{
j -= 2;
i++;
continue;
}
else
magicSquare[i][j] = num++;   
  
j++; i--;
}
  
  
  
for (i = 0; i < n; i++)
{
for (j = 0; j < n; j++)
cout<<roman(magicSquare[i][j])<<" ";
cout<<endl;
}
}
  

int main()
{
int n = 3;
generateSquare (n);
return 0;
}