1. 2 SO3(g) ⇄ 2 SO2(g) + O2(g) Kp = 1.2× 10-5 0.60 atm of SO3...
1. 2 SO3(g) ⇄ 2 SO2(g) +
O2(g) Kp = 1.2× 10-5
0.60 atm of SO3 and 0.30 atm of SO2are placed
in a container and the system is allowed to reach equilibrium.
Calculate the pressure of O2(g) at equilibrium.?
2. Find the pH of 0.68 M HCOOH(aq) given that its Ka = 1.8×10-4.
2 questions please answer both
Homework Answers
The equilibrium constant in terms of pressures, Kp, for the reaction of SO2 and O2 to...
The equilibrium constant in terms of pressures, Kp, for the reaction of SO2 and O2 to form SO3 is 0.365 at 1.15×103 K: SO2(g) + O2(g) = 2SO3(g) A sample of SO3 is introduced into an evacuated container at 298 K and allowed to dissociate until its partial pressure reaches an equilibrium value of 0.867 atm. Calculate the equilibrium partial pressures of SO2 and O2 in the container. PSO2 = PO2 =
5) For the reaction 2 SO2(g) + O2(g) → 2 SO3(g), if initially P(SO2) = 1.2...
5) For the reaction 2 SO2(g) + O2(g) → 2 SO3(g), if initially P(SO2) = 1.2 atm, P(O2) = 1.8 atm, and P(SO3) = 2.1 atm, calculate AG for this reaction at 25°C. The following data is valid at 25°C: AG° (kJ/mol) SO 300.4 SO3 370.4 A) -140.0 kJ/mol B)-141.3 kJ/mol C)-138.7 kJ/mol D) 1,174.7 kJ/mol E) -137.6 kJ/mol
For the equilibrium: 2 SO3(g) < = > O2(g) + 2 SO2(g) Kp = 0.269 at...
For the equilibrium: 2 SO3(g) < = > O2(g) + 2 SO2(g) Kp = 0.269 at 625 oC What is Kc at this temperature? Kp = Kc[RT]Δn R = 0.08206 L-atm/mol K
2) For the equilibrium: 2 SO3(g) <=> O2(g) + 2 SO2(g) Kp = 0.269 at 625...
2) For the equilibrium: 2 SO3(g) <=> O2(g) + 2 SO2(g) Kp = 0.269 at 625 °C What is Ke at this temperature? Kp = Kc[RT]An R = 0.08206 L-atm/mol K
2 NOCl(g) ⇄ 2 NO(g) + Cl2(g) Kp = 7.2× 10-6 1.50 atm of NOCl(g) is...
2 NOCl(g) ⇄ 2 NO(g) + Cl2(g) Kp = 7.2× 10-6 1.50 atm of NOCl(g) is placed in a container and the system is allowed to reach equilibrium. Calculate the equilibrium pressure of Cl2(g) at equilibrium. 4.8 × 10-2 atm 8.5 × 10-3 atm 3.2 × 10-2 atm 2.4 × 10-2 atm 1.6 × 10-2 atm
The equilibrium constant, Kp, for the following reaction is 2.74 at 1.15x103K. 2803(g) 22502(g) + O2(g)...
The equilibrium constant, Kp, for the following reaction is 2.74 at 1.15x103K. 2803(g) 22502(g) + O2(g) + If an equilibrium mixture of the three gases in a 10.9 L container at 1.15*10²K contains SO3 at a pressure of 1.77 atm and SO2 at a pressure of 0.926 atm, the equilibrium partial pressure of O2 is atm.
Consider the following equilibrium reaction : Heat + 2 SO2 (g) + O2(g) ↔ 2 SO3(g) Assume the above...
Consider the following equilibrium reaction : Heat + 2 SO2 (g) + O2(g) ↔ 2 SO3(g) Assume the above reaction is allowed to reach equilibrium prior to the following changes. Answer the following questions by writing increase, decrease or remain the same on the line. **please also explain why** If the reaction mixture is heated up , the value of the equilibrium constant will _______________________ If SO2 (g) is added to the reaction vessel the concentration of O2(g) will____________________________. If SO3 (g) is...
For the reaction 2 SO3 (g) equilibrium reaction arrow 2 SO2 (g) + O2 (g) Kp...
For the reaction 2 SO3 (g) equilibrium reaction arrow 2 SO2 (g) + O2 (g) Kp = 0.335 at 1000 K. Calculate Kc at 1000 K. Please help.
For the equilibrium 2 SO3(g) <----> 2 SO2(g) + O2(g), Kc is 4.08 * 10-3 at...
For the equilibrium 2 SO3(g) <----> 2 SO2(g) + O2(g), Kc is 4.08 * 10-3 at 1000 K. Calculate the value for Kp.
2 SO2 (g) + O2 (g) = 2 SO3 (g) + Energy Predict the effect of...
2 SO2 (g) + O2 (g) = 2 SO3 (g) + Energy Predict the effect of each of the following changes on the number of moles of S03 present in the mixture at equilibrium Decreasing the volume of the system Adding oxygen to the equilibrium mixture Raising the temperature of the system Decreasing the pressure of the system Adding a catalyst 2 SO2 (g) + O2 (g) = 2 SO3 (g) + Energy Predict the effect of each of the...
5) For the reaction 2 SO2(g) + O2(g) → 2 SO3(g), if initially P(SO2) = 1.2 atm, P(O2) = 1.8 atm, and P(SO3) = 2.1 atm, calculate AG for this reaction at 25°C. The following data is valid at 25°C: AG° (kJ/mol) SO 300.4 SO3 370.4 A) -140.0 kJ/mol B)-141.3 kJ/mol C)-138.7 kJ/mol D) 1,174.7 kJ/mol E) -137.6 kJ/mol
2) For the equilibrium: 2 SO3(g) <=> O2(g) + 2 SO2(g) Kp = 0.269 at 625 °C What is Ke at this temperature? Kp = Kc[RT]An R = 0.08206 L-atm/mol K
The equilibrium constant, Kp, for the following reaction is 2.74 at 1.15x103K. 2803(g) 22502(g) + O2(g) + If an equilibrium mixture of the three gases in a 10.9 L container at 1.15*10²K contains SO3 at a pressure of 1.77 atm and SO2 at a pressure of 0.926 atm, the equilibrium partial pressure of O2 is atm.
2 SO2 (g) + O2 (g) = 2 SO3 (g) + Energy Predict the effect of each of the following changes on the number of moles of S03 present in the mixture at equilibrium Decreasing the volume of the system Adding oxygen to the equilibrium mixture Raising the temperature of the system Decreasing the pressure of the system Adding a catalyst 2 SO2 (g) + O2 (g) = 2 SO3 (g) + Energy Predict the effect of each of the...
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