Part A= Calculate the [H3O+] of the following polyprotic acid solution: 0.350 M H3PO4.
Part B= Calculate the pH of this solution.
Part A
The acid dissociation goes like (assuming full dissociation)
-
Thus , 1 mole of
produces 3 moles of
Hence the
will be 3 times of 
Hence the
Part B
For calculating pH of weak acid , we need to know it's ka value .
But this is not provided in the question . So , we have to use
the general equation of pH , that is


But this value is getting negative , that is not the correct way . Actually , we are missing the ka value .Also, pH equation that we used is strictly used for dilute solutions . But for this concentrated solution , we need to use Hammet Acidity Function , but here due to insufficient data , we cannot use that . So , our final answer gives error .
Part A= Calculate the [H3O+] of the following polyprotic acid solution: 0.350 M H3PO4. Part B=...
Part A= Calculate the [H3O+] of the following polyprotic acid solution: 0.350 M H3PO4. Part B= Calculate the pH of this solution. Part C= Calculate the [H3O+] and pH of the following polyprotic acid solution: 0.300 M H2C2O4. Part D= Calculate the pH of this solution.
Calculate the [H3O+] and pH of the following polyprotic acid solution: 0.350 M H2C2O4.
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Calculate the [H3O+] of the following polyprotic acid solution: 0.400 M H3PO4 without using an ICE table
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