Dilution: Find the concentration of [OH-] if 20.1 mL of 0.403 M NaOH stock solution is added to 46.1 mL of CV solution. (Assume the volumes are additive.) I got 0.0060876133 or at 4 decimal places 0.00601 and its saying its wrong.
Dilution: Find the concentration of [OH-] if 20.1 mL of 0.403 M NaOH stock solution is...
20. If 10 mL of 0.05 M NaOH is added to a 20 mL solution of 0.1 M NaNO2 and 0.1 M HNO2, what will be the pH of the resultant solution? Assume that volumes are additive. Ka for HNO2 = 7.1x10-4. 21. At 25°C, 50.0 mL of 0.50 M NaOH(aq) is added to a 250 mL aqueous solution containing 0.30 M NH3 and 0.36 M NH4Cl. What is the pH of the solution after the addition of the base?...
Question 1 20 pts Please prepare 20 mL of 0.2 M NaOH, given a stock solution of 0.6 M NaOH. State the precise amount of the 0.6 M NaOH used and the amount of diluent (H2O) added Question 2 20 pts Please prepare 500 mL of a 1/100 dilution of serum from a tube with a 1/10O dilution of serum. Please state the volume of the 1/10 dilution of serum used and the volume of diluents (H2O) used 20 pts...
You mix 23.0 mL of 0.225 M FeCl3 with 44.5 mL of 0.461 M NaOH. What mass of Fe(OH)3 (in grams) will precipitate from this reaction mixture? Mass = g One of the reactants (FeCl3 or NaOH) is present in a stoichiometric excess. What is the molar concentration of the excess reactant remaining in solution after Fe(OH)3 has been precipitated? Assume the volumes are additive. Concentration = M
You mix 23.0 mL of 0.225 M FeCl3 with 44.5 mL of 0.461 M NaOH. What mass of Fe(OH)3 (in grams) will precipitate from this reaction mixture? Mass = g One of the reactants (FeCl3 or NaOH) is present in a stoichiometric excess. What is the molar concentration of the excess reactant remaining in solution after Fe(OH)3 has been precipitated? Assume the volumes are additive. Concentration = M
a) 2.00 (IV) It is desired to prepare 0.250 L of a 0.100 M solution of NaCl from a 1.00 M stock solution. How many mL of the stock solution must be taken for the dilution? (V) What volume of a 0.500 M HCl solution is needed to neutralize 10.0 mL of a 0.300 M NaOH solution. (VI) What volume of 0.416 M Mg(NO3)2 should be added to 255 mL of 0.102 M KNO, to produce a solution with a...
Part A Find (OH] for a 0.036 M solution of NaOH. Express the concentration to two significant figures and include the appropriate ur C: Å * O O ? [OH-] = Value Units Submit Request Answer Part B. Find the pH of a 0.036 M NaOH solution. Express your answer to two decimal places. pH = 12.56 Submit Previous Answers Correct
Indicate the concentration of each ion present in the solution formed by mixing the following. A. 42.0 mL of 0.140 M NaOH and 37.6 mL of 0.400 M NaOH. Assume that the volumes are additive. B. 44.0 mL of 0.100 M Na2SO4 and 25.0 mL of 0.200 M KCl. Assume that the volumes are additive. C. 3.30 g KCl in 75.0 mL of 0.280 M CaCl2 solution. Assume that the volumes are additive.
Indicate the concentration of each ion present in the solution formed by mixing the following. A. 42.0 mL of 0.150 M NaOH and 37.6 mL of 0.410 M NaOH. Assume that the volumes are additive. B. 44.0 mL of 0.140 M Na2SO4 and 25.0 mL of 0.160 M KCl. Assume that the volumes are additive. C. 3.20 g KCl in 75.0 mL of 0.220 M CaCl2 solution. Assume that the volumes are additive.
A 20.0 mL sample of 0.200 M HBr solution is titrated with 0.200 M NaOH solution. Calculate the pH of the solution after the following volumes of base have been added. Part A 16.0 mL Express your answer using two decimal places. ΤΕΙ ΑΣφ BY pH = Submit Request Answer Part B 19.8 ml Express your answer using two decimal places. VO AEC pH- Submit Previous Answers Request Answer Problem 17.43 A 20.0 mL sample of 0.200 M HBr solution...
Calculate the new molarity if the following dilution is made. Assume the volumes are additive. a 56.0 mL of water is added to 25.2 mL of 0.174 M NaCl solution. Molarity = b 143 mL of water is added to 48.2 mL of 0.581 M NaOH solution. Molarity = M C 557 mL of water is added to 160. mL of 4.84 M KOH solution. Molarity = d 181 mL of water is added to 68.1 mL of 1.27 M...