A student begins with 9.6 mL of a 0.28 M Cu(NO3)2 solution and performs the copper...
A student begins with 9.6 mL of a 0.28 M Cu(NO3)2 solution and performs the copper cycle lab. She recovers 0.070 grams of copper metal.
What is the theoretical yield of copper in grams?
Homework Answers
volume , V = 9.6 mL
= 9.6*10^-3 L
use:
number of mol,
n = Molarity * Volume
= 0.28*9.6*10^-3
= 2.688*10^-3 mol
This is number of moles of Cu(NO3)2
one mole of Cu(NO3)2 contains 1 moles of Cu
use:
number of moles of Cu = 1 * number of moles of Cu(NO3)2
= 1 * 2.688*10^-3
= 2.688*10^-3
Molar mass of Cu = 63.55 g/mol
use:
mass of Cu,
m = number of mol * molar mass
= 2.688*10^-3 mol * 63.55 g/mol
= 0.1708 g
Answer: 0.171 g
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