A ball is dropped from a very tall building. How far will it have fallen after 3.6s?
as it is dropped its initial velocity is zero.
from kinematics equation s = ut + 1/2 gt^2
distance it covered in t = 3.6s is
h = 0 + 1/2 *9.8*(3.6^2)
= 63.5 m
A ball is dropped from a very tall building. How far will it have fallen after...
Use kinematic equations.
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