Question

Hi, my JS function returns the new array with latest "time" objects and merging all "pics" and "videos". I just need to make an output of an array in order that was originally given(personnelMateriaRel, videos, contactor, pics, distributionResult, sendTime)

var data = [

/*Object 1*/

  {

    "personnelMateriaRel": [],

    "videos": [],

    "contactor": {

      "id": 18320,

      "mobile": "13705139529",

      "name": "Jack",

      "otherTel2": "",

      "temobile": "",

      "workUnit": ""

    },

    "pics": [],

    "distributionResult": {

      "latitude": 23.095949110729155,

      "longitude": 113.28544487112273,

      "time": "2020-01-02 17:04:38",

      "content": "Arrived",

      "address": "USA"

    },

    "sendTime": "2020-01-02 16:01:54"

  },

  /*Object 2*/

  {

    "personnelMateriaRel": [],

    "videos": [],

    "contactor": {

      "id": 18320,

      "mobile": "13705139529",

      "name": "Jack",

      "otherTel2": "",

      "temobile": "",

      "workUnit": ""

    },

    "pics": [],

    "distributionResult": {

      "latitude": 23.09594105827961,

      "longitude": 113.28548480963536,

      "time": "2020-01-02 17:34:27",

      "content": "Arrived",

      "address": "USA"

    },

    "sendTime": "2020-01-02 17:08:49"

  },

  /*Object 3*/

  {

    "personnelMateriaRel": [],

    "videos": [],

    "contactor": {

      "id": 18320,

      "mobile": "13705139529",

      "name": "Jack",

      "otherTel2": "",

      "temobile": "",

      "workUnit": ""

    },

    "pics": [],

    "distributionResult": {

      "latitude": 23.09594105827961,

      "longitude": 113.28548480963536,

      "time": "2020-01-02 17:34:27",

      "content": "Arrived",

      "address": "USA"

    },

    "sendTime": "2020-01-02 17:08:49"

  }

]

function resolve(array) {

  let map = {};

  let keys = ["pics","videos","personnelMateriaRel"];

  array.forEach(element => {

    let id = element.contactor.id;

    let eleTime = element.distributionResult.time;

    let object = map[id]

    if (!object) {

      object = map[id] = {

        contactor: element.contactor,

        distributionResult: element.distributionResult,

        sendTime: element.sendTime

      }

    } else {

      let lastTime = object.distributionResult.time;

      if (eleTime >= lastTime) {

        object.contactor = element.contactor;

        object.distributionResult = element.distributionResult;

        object.distributionResult.time = eleTime;

        object.sendTime = element.sendTime;

      }

    }

    for (let value of keys) {

      object[value] = object[value] ?

        object[value].concat(element[value]) : [].concat(element[value])

    }

  });

  return Object.keys(map).map(id => map[id])

}

console.log(resolve(data));

/*If you run the above code you will understand what i mean*/

Answer 1

An object is not an ordered data structure, so no matter what, it will always be printed in alphabetical order. However, there is a workaround which has been explained in the comments at the end of the code. You can run the code to understand.

SOURCE CODE:

var data = [

  /*Object 1*/

  {

    personnelMateriaRel: [],

    videos: [],

    contactor: {

      id: 18320,

      mobile: "13705139529",

      name: "Jack",

      otherTel2: "",

      temobile: "",

      workUnit: ""

    },

    pics: [],

    distributionResult: {

      latitude: 23.095949110729155,

      longitude: 113.28544487112273,

      time: "2020-01-02 17:04:38",

      content: "Arrived",

      address: "USA"

    },

    sendTime: "2020-01-02 16:01:54"

  },

  /*Object 2*/

  {

    personnelMateriaRel: [],

    videos: [],

    contactor: {

      id: 18320,

      mobile: "13705139529",

      name: "Jack",

      otherTel2: "",

      temobile: "",

      workUnit: ""

    },

    pics: [],

    distributionResult: {

      latitude: 23.09594105827961,

      longitude: 113.28548480963536,

      time: "2020-01-02 17:34:27",

      content: "Arrived",

      address: "USA"

    },

    sendTime: "2020-01-02 17:08:49"

  },

  /*Object 3*/

  {

    personnelMateriaRel: [],

    videos: [],

    contactor: {

      id: 18320,

      mobile: "13705139529",

      name: "Jack",

      otherTel2: "",

      temobile: "",

      workUnit: ""

    },

    pics: [],

    distributionResult: {

      latitude: 23.09594105827961,

      longitude: 113.28548480963536,

      time: "2020-01-02 17:34:27",

      content: "Arrived",

      address: "USA"

    },

    sendTime: "2020-01-02 17:08:49"

  }

];

function resolve(array) {

  let map = {};

  let keys = ["pics", "videos", "personnelMateriaRel"];

  array.forEach(element => {

    let id = element.contactor.id;

    let eleTime = element.distributionResult.time;

    let object = map[id];

    if (!object) {

      object = map[id] = {

        contactor: element.contactor,

        distributionResult: element.distributionResult,

        sendTime: element.sendTime

      };

    } else {

      let lastTime = object.distributionResult.time;

      if (eleTime >= lastTime) {

        object.contactor = element.contactor;

        object.distributionResult = element.distributionResult;

        object.distributionResult.time = eleTime;

        object.sendTime = element.sendTime;

      }

    }

    for (let value of keys) {

      object[value] = object[value]

        ? object[value].concat(element[value])

        : [].concat(element[value]);

    }

  });

  return Object.keys(map).map(id => map[id]);

}

//When returning an array of objects, it will always be printed in alphabetical order since objects aren't ordered.

//However, arrays are ordered and we can convert the object to an array as shown below

console.log(

  //Map the array

  resolve(data).map(

    d =>

      //Use the object d and create an array of its properties in any order you prefer

      [

        `personnelMateriaRel: ${JSON.stringify(d.personnelMateriaRel)}`,

        `videos: ${JSON.stringify(d.videos)}`,

        `contactor: ${JSON.stringify(d.contactor)}`,

        `pics: ${JSON.stringify(d.pics)}`,

        `distributionResult: ${JSON.stringify(d.distributionResult)}`,

        `sendTime: ${JSON.stringify(d.sendTime)}`

      ].join(`, `)

    //And then join it with a comma

  )

);

SCREENSHOTS: