As 50.0 mL of 0.10 M HCl is added to 0.40 M HCl, what happens to...
As 50.0 mL of 0.10 M HCl is added to 0.40 M HCl, what happens to the pH of the original solution?
Homework Answers
This is incomplete question. Volume of 0.40 M HCl is not given.
I am considering it to be 1 L (1000 mL), change according to the given value in question in place of V2 (in image attched below) and method remains same.
Here M2 = 0.40 M. So pH= - log M2 = - log(0.40) = 0.398
So pH increases on addition of 50.0 mL 0.10 M HCl.
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