A sealed container holding 0.0255 L0.0255 L of an ideal gas at 0.997 atm0.997 atm and...
A sealed container holding 0.0255 L0.0255 L of an ideal gas at 0.997 atm0.997 atm and 73 ∘C73 ∘C is placed into a refrigerator and cooled to 35 ∘C35 ∘Cwith no change in volume. Calculate the final pressure of the gas.
Homework Answers
pressure P1 = 0.997 atm
pressure P2 = ??
temperature T1 = 73 oC = 346 K
T2 = 35 oC = 308 K
P1 / T1 = P2 / T2
0.997 / 346 = P2 / 308
P2 = 0.888
final pressure = 0.888 atm
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