Question

C++ programming exercise:

A milk carton can hold 3.78 liters of milk. Each morning, a dairy farm ships cartons of milk to a local grocery store. The cost of producing one liter of milk and the profit of each carton of milk vary from farm to farm.

Write a program that prompts the user to enter:

1. The total amount of milk produced in the morning.

2. The cost of producing one liter of milk.

3. The profit on each carton of milk.

The program then outputs:

1. The number of milk cartons needed to hold milk.

   • Round your answer to the nearest integer.

2. The cost of producing milk.

3. The profit for producing milk.

Answer 1

Program:

#include <iostream>
#include <iomanip>
#include<cmath>

using namespace std;

int main()
{
   //constant to indicate how many liters of milk can each carton hold
   const double MILK_IN_EACH_CARTON = 3.78;
   //variable declarations
    double milkProduced, productionCostPerLiter, profitPerCarton;
    int cartonsRequired;
    double costOfProducingMilk, profit;
  
    //prompt and read milk produced
    cout << "Enter total amount of milk produced in the morning: ";
    cin >> milkProduced;
    //prompt and read cost of producing 1 liter of milk
    cout << "Enter the cost of producing one liter of milk: ";
    cin >> productionCostPerLiter;
    //prompt and read profit on each carton of milk
    cout << "Enter profit on each carton of milk: ";
    cin >> profitPerCarton;
  
    //calculate the number of carton required
    cartonsRequired = (round) (milkProduced / MILK_IN_EACH_CARTON);
    //calculate the cost of producing milk
    costOfProducingMilk = productionCostPerLiter * milkProduced;
    //calculate the profit
    profit = cartonsRequired * profitPerCarton;
  
    //display output
    cout << "\nNumber of cartons required: " << cartonsRequired << endl;
    cout << "Cost for producing milk: $" << fixed << setprecision(2) << costOfProducingMilk << endl;
    cout << "Profit for producing milk: $" << fixed << setprecision(2) << profit << endl;
    return 0;
}

Output:

Program Screenshot: