Question

Copy the program DigitPlay.java and implement the TBI (To Be Implemented) method named play(Result r).

Your program cannot contain any import statements.

Your play(Result r) method cannot call any other methods.

The output of your program must match the following.

number: 5
      # of digits: 1
   smallest digit: 5
    largest digit: 5
      digit range: 0
        digit sum: 5
    digit average: 5.0
    digit product: 5

number: 42
      # of digits: 2
   smallest digit: 2
    largest digit: 4
      digit range: 2
        digit sum: 6
    digit average: 3.0
    digit product: 8

number: 127
      # of digits: 3
   smallest digit: 1
    largest digit: 7
      digit range: 6
        digit sum: 10
    digit average: 3.3333333333333335
    digit product: 14

number: 1024
      # of digits: 4
   smallest digit: 0
    largest digit: 4
      digit range: 4
        digit sum: 7
    digit average: 1.75
    digit product: 8 (no multiply by 0)

number: 32767
      # of digits: 5
   smallest digit: 2
    largest digit: 7
      digit range: 5
        digit sum: 25
    digit average: 5.0
    digit product: 1764

number: 2147483647
      # of digits: 10
   smallest digit: 1
    largest digit: 8
      digit range: 7
        digit sum: 46
    digit average: 4.6
    digit product: 903168

number: 9223372036854775807
      # of digits: 19
   smallest digit: 0
    largest digit: 9
      digit range: 9
        digit sum: 88
    digit average: 4.631578947368421
    digit product: 179233689600 (no multiply by 0)

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Digitplay program:

/*
 * This Java program takes a positive integer of type long
 * and prints the following about its digits:
 *
 *     + the number of digits
 *     + the smallest digit
 *     + the largest digit
 *     + the range of the digits
 *     + the sum of the digits
 *     + the average of the digits (digit 0 is included)
 *     + the product of the digits (digit 0 is excluded)
 */

public class DigitPlay {

   public static final String INDENT = "\n   ";

   public static void main(String[] argv) {
      long[] data = { 5, 42, Byte.MAX_VALUE, 1024, Short.MAX_VALUE,
                      Integer.MAX_VALUE, Long.MAX_VALUE };
      for (int i = 0; i < data.length; i++)
         print(play(new Result(data[i])));
   }

   public static void print(Result r) {
      System.out.print("number: " + r.number +
                        INDENT + "   # of digits: " + r.ndigits +
                        INDENT + "smallest digit: " + r.min + 
                        INDENT + " largest digit: " + r.max + 
                        INDENT + "   digit range: " + r.range + 
                        INDENT + "     digit sum: " + r.sum + 
                        INDENT + " digit average: " + r.avg + 
                        INDENT + " digit product: " + r.product);
      if (r.has0) System.out.print(" (no multiply by 0)");
      System.out.println("\n");
   }

   static class Result {
      public long number;
      public int ndigits;
      public int min = 10;
      public int max = -1;
      public int range;
      public int sum;
      public long product = 1;
      public double avg;
      public boolean has0;
      public Result(long n) { number = n; }
   }

   /** 
    * TBI (To Be Implemented)...
    *
    * Using a number stored a Result object, this method fills in 
    * the following information about the digits of the number: 
    * # of digits; smallest digit; largest digit; digit range; 
    * digit sum; digit average; flag if number contains a 0;
    * digit product that excludes multiplying by 0 digits
    *
    * @param Result object r to fill in for r.number
    * @return the filled in Result object r
    */
   public static Result play(Result r) {
      return r;
   }

}

Answer 1

Solution:

/*
 * This Java program takes a positive integer of type long
 * and prints the following about its digits:
 *
 *     + the number of digits
 *     + the smallest digit
 *     + the largest digit
 *     + the range of the digits
 *     + the sum of the digits
 *     + the average of the digits (digit 0 is included)
 *     + the product of the digits (digit 0 is excluded)
 */
public class DigitPlay {

    public static final String INDENT = "
   ";

    public static void main(String[] argv) {
        long[] data = {5, 42, Byte.MAX_VALUE, 1024, Short.MAX_VALUE,
                Integer.MAX_VALUE, Long.MAX_VALUE};
        for (int i = 0; i < data.length; i++)
            print(play(new Result(data[i])));
    }

    public static void print(Result r) {
        System.out.print("number: " + r.number +
                INDENT + "   # of digits: " + r.ndigits +
                INDENT + "smallest digit: " + r.min +
                INDENT + " largest digit: " + r.max +
                INDENT + "   digit range: " + r.range +
                INDENT + "     digit sum: " + r.sum +
                INDENT + " digit average: " + r.avg +
                INDENT + " digit product: " + r.product);
        if (r.has0) System.out.print(" (no multiply by 0)");
        System.out.println("
");
    }

    static class Result {
        public long number;
        public int ndigits;
        public int min = 10;
        public int max = -1;
        public int range;
        public int sum;
        public long product = 1;
        public double avg;
        public boolean has0;

        public Result(long n) {
            number = n;
        }
    }

    /**
     * TBI (To Be Implemented)...
     * <p>
     * Using a number stored a Result object, this method fills in
     * the following information about the digits of the number:
     * # of digits; smallest digit; largest digit; digit range;
     * digit sum; digit average; flag if number contains a 0;
     * digit product that excludes multiplying by 0 digits
     * <p>
     * param Result object r to fill in for r.number
     * return the filled in Result object r
     */
    public static Result play(Result r) {

        long temp = r.number;
        int d1 = 0;
        long d2, sum = 0, product = 1;

        //To find number of digits
        while (temp != 0) {
            temp = temp / 10;
            d1 = d1 + 1;
        }
        r.ndigits = d1;
        temp = r.number;
        //To find minimum valued digit
        while (temp != 0) {
            d2 = temp % 10;
            if (d2 < r.min)
                r.min = (int) d2;
            temp = temp / 10;
        }
        temp = r.number;
        //To find maximum valued digit
        while (temp != 0) {
            d2 = temp % 10;
            if (d2 > r.max)
                r.max = (int) d2;
            temp = temp / 10;
        }
        //To find range
        r.range = r.max - r.min;
        temp = r.number;
        //To find sum of digits
        while (temp != 0) {
            d2 = temp % 10;
            sum = sum + d2;
            temp = temp / 10;
        }
        r.sum = (int) sum;
        temp = r.number;
        //To find product of digits
        while (temp != 0) {
            d2 = temp % 10;
            if (d2 != 0)
                product = product * d2;
            //To check if a particular digit is 0
            if (d2 == 0)
                r.has0 = true;
            temp = temp / 10;
        }
        r.product = product;
        //To find average of digits
        r.avg = (double) r.sum / r.ndigits;

        return r;
    }

}

Output: