An earth satellite moves in a circular orbit at a speed of 5,800 m/s. What is...

Question

Question

An earth satellite moves in a circular orbit at a speed of 5,800 m/s. What is its orbital period in minutes?

science physics

Answer 1

Answer #1

orbital distance

v^2 = GM / R

5800^2 = 6.67* 10^-11* 5.98* 10^24 / R

R = 1.1857* 10^7 m

now

T = 2 pi R / v

T = 213.97 mins

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Answer 2

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