A spring has a equilibrium length of 0.100 m. When a force of 40.0 N is...
A spring has a equilibrium length of 0.100 m. When a force of 40.0 N is applied to the spring, the spring has a length of 0.140 m. What is the value of the spring constant of this spring?
Homework Answers
force applied on the spring = spring constant * change in length of spring
F = kx
where k = spring constant
x = extension in the spring
40 = k*(0.14 - 0.1)
k = 1000 N/m
so the spring constant of the spring is 1000 N/m
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