Which of the following would cause the percent ionization of HNO2 to decrease? A: addition of NaCl B: addition of NaNO2 C: addition of HCl D: diluting with more water.
Common ion effect describes the suppressing effect on ionisation of an electrolyte when other electrolyte is added which shares a common ion.
Common ion effect works using Le Chaterlier's principle which states that if a dynamic equilibrium is distributed by changing the conditions the position of equilibrium shifts in such a way to counteract the change.
B. Addition of NaNO2 will decrease the percent ionisation of HNO2.
As the concentration of NO2- will increase to decrease the concentration of NO2- the position of equilibrium will shift towards the left i.e towards HNO2.

Which of the following would cause the percent ionization of HNO2 to decrease? A: addition of...
14. (three marks) Which of the following would cause crystallization of NaCl from a solution? a heating the solution to evaporate the water b. dissolving more NaCl to cause supersaturation c. cooling a saturated solution d. diluting a saturated solution e. a, b, and e only 15. (three marks, Why is temperature decreased in the crucial step of the Solvay process? Na:CO, is more soluble b. NaHCO, is crystallized NaCl is less soluble d. CaCO, is more soluble e none...
Consider the following equilibrium for nitrous acid, HNO2, a weak acid: HNO2 (aq) + H2O (l) <--------------> H3O+ (aq) + NO2- In which direction will the equilibrium shift if a) NaOH is added? b) NaNO2 is added? c) HCl is added? d) The acid solution is made more dilute?
Question 31 (1 point) Which sets would form a buffer? HCl and NaCl HNO2 and NaNO2 NH4NO3 and HNO3 NH4NO3 and NH3 o BE 66 F9 F10 F11 F12 ( 5 6 7 8 9 0
6. If you add 0.1 M NaNO2 to 0.1 M HNO2 (see the reaction below) will the pH change? HNO2(aq) + H2O(e) = H30*(aq) + NO2 (aq) A. No, because neither Nat or NO2 will change the pH. B. No, because of Le Châtliers Principle. C. Yes, because Nat will change the pH. D. Yes, because of Le Châtliers Principle. E. Yes, because the addition of salt always increases the ionization of water.
Which would cause an increase in the demand for product A? a. A decrease in the number of suppliers of product B b. An increase in the cost of producing product A c. A decrease in the price of a complementary product B d. A decrease in the price of product A
) Which of the following substances would cause the greatest drop in the freezing temperature if we dissolve 1 mol in a fixed amount of water? A) C6H12O6 (fructose) B) KNO3 C) NaCl D) CaCl2 E) All of these solutions would freeze at the same temperature.
Which of the following would cause the price of equity to decrease according to the dividend discount model? a. none of the other choices are correct b. an increase in the discount rate c. an increase in expected future dividends d. an increase in the growth rate of expected future dividends
(YES/NO) (ADDED ACID/ADDED BASE)
A buffer solution that is 0.322 M in HNO2 and 0.322 M in NaNO, has a pH of 3.35. Addition of which of the following would increase the capacity of the buffer for added OH"? (Select all that apply.) OHNO2 pure water O both HNO, and NaNO2 NaNO2 Onone of the above Use the References to access important values if needed for this question. The PK, value for HNO2 is 3.35. Would a buffer prepared from...
Which of the following would be expected to cause a decrease in the quantity supplied of a certain good? 6. a. b. c. d. A decrease in the cost of materials used in producing that good An increase in the cost of materials used in producing that good A decrease in the price of the good An increase in the price of the good Suppose that at a price of $70 the quantity supplied in a market is 10 units,...
Which of the following combinations would make a buffer with pH close to 3.0? HClO2 Ka = 1.1 × 10-2 NH3 Kb = 1.8 × 10-5 HNO2 Ka = 7.2 × 10-4 C5H5N Kb = 1.5 × 10-9 Equal volumes of 0.10 M NH4Cl and 0.10 M NH3 Equal volumes of 0.10 M HClO2 and 0.10 M NaClO2 Equal volumes of 0.10 M HNO2 and 0.10 M NaNO2 Equal volumes of 0.10 M HCl and 0.10 M NaCl Equal volumes...