B) 8.7*10^-10 M NaOH
When concentration of soecies involved is so low then we consider contribution from water as well.
For eg. Water is composed of H+ and OH- ions
and [H+][OH-] = 10^-14
So [H+] =[OH-] = 10^-7
Total [OH-] in the solution is 10^-7 + 8.7*10^-10
[OH-] = 10^-10(10^3 + 8.7)
[OH-] = 10^-10(1000+8.7)
[OH-] = 1008.7*10^-10
POH = -log( 1008.7*10^-10)
POH = 6.99
So ph = 14- poh
Ph = 7.00 is the answer
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