Question

1).  the roller coaster car with a mass of 250 kg starts with an initial speed v0 = 5.6 m/s at the top of the track . What is its speed (in m/s) at the lowest point of the track (which is 25m below the start point)? Keep 2 decimal places.

1 b) Recall what you learned in vertical circular motion.

If the lowest part of the track is approximated as circular with a radius of 6.20 m, What is the magnitude of the normal force (in Newtons) on the roller coaster car?

Don't use scientific notation.

2) As shown in the figure, a 11 kg block moves with an intial speed of 8.0 m/s on a rough floor. The coefficient of kinetic friction between the block and the floor is μk = 0.27.

You will find the distance through which the block slows down and comes to a stop.

(a) Solve for the magnitude of the normal force FN, it is:

a 2. What is the work (in Joules) done by the normal force? Pay attention to the angle in the work formula and the sign of work. Hint: even though the distance is not known yet, this question can still be answered.

(b) What is the work done by the gravitational force? Pay attention to the angle in the work formula and the sign of work. Hint: even though the distance is not known yet, this question can still be answered.

(c) What is the magnitude of the kinetic frictional force (in Newtons)?

(d) Write the work done by the kinetic frictional force in terms of the distance (distance is unknown). Pay attention to the angle in the work formula and the sign of work.

Apply the Work-Kinetic Energy Theorem:

What is the distance (in meters) after which the block comes to a stop?

d 2). Now the situation changes to:

The same block of 11 kg moves with the same intial speed of 8.0 m/s on another rough floor. The coefficient of kinetic friction between the block and the other floor μk is unknown. It is measured that the block comes to a stop after moving through a distance of 20.09 m. What is the μk ?

Answer 1

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