Question

def oddify(...): The caller will supply a list of ints named xs, and might also provide a list named evens. Remove all even numbers from xs, and put them either at the end of the evens list (when provided) or into a new list (when evens was not provided). Return the evens (or newly created) list. Assume id(xs) != id(evens). all in python

Answer 1

def oddify(xs, evens = []):
    for x in xs:
        if(x%2==0):
            evens.append(x)
    return evens

# Testing
print(oddify([5,2,4,1,3]))
print(oddify([5,2,4,1,3],[6,8]))