Question

A gas has a Henry's law constant of 0.183 M/atmM/atm . How much water would be needed to completely dissolve 1.70 LL of the gas at a pressure of 735 torrtorr and a temperature of 34 ∘C∘C?

Answer 1

1)

Henry's law constant kH = 0.183 M/atm

pressure P = 735 torr = 0.9671 atm

concentration = kH x P

                      = 0.183 x 0.9671

                      = 0.177 M

from idea gas law :

P V = n R T

0.967 x 1.70 = n x 0.0821 x (34 + 273)

n = 0.0652 mol

volume = moles / concentration

            = 0.0652 / 0.177

volume = 0.368 L

volume of water = 0.368 L