A balance and torque experiment is conducted with an UN-balanced ruler.
Length of the ruler: 1 m
Mass of the ruler: 193 g
The pivot is at the 35-cm mark.
A 46-g mass is located at the 82-cm mark of the ruler.
We want to balance the ruler by placing another mass at the 19-cm mark.
What should be magnitude of this additional mass?
Balancing the torque about the pivot point,
M x (35 - 19) = 193(50 - 35) + 46(82 - 35)
M x 16 = 2895 + 2162
M = 316.06 g
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A balance and torque experiment is conducted with an UN-balanced ruler. Length of the ruler: 1...
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