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A rock is thrown horizontally off the top of half-dome which is 2700m above the valley...

A rock is thrown horizontally off the top of half-dome which is 2700m above the valley floor below. If the initial velocity was 30.0 m/s, how far will the rock land from the bottom of the cliff? Use g=9.80 m/s^2, ignore air resistance/drag. sf = si + Vis(Delta t) + 1/2 as (Delta t)^2 Vf = Vi + a(Delta t)

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