For the titration of 20.00 mL of 0.375 M pyridine using 0.150 M HBr, what is the pH after 30.00 mL of HBr has been added?
pKa of pyridine = 5.23
millimoles of pyridine = 20 x 0.375 = 7.5
millimoles of HBr = 0.150 x 30 = 4.5
C5H5N + HBr -----------------------------> C5H5NH+ + Br-
7.5 4.5 0 0
3 0 4.5 0
pH = pKa + log [C5H5N / C5H5NH+]
pH = 5.23 + log (3 / 4.5)
pH = 5.05
note : if anything goes wrong. please check your Kb value with my Kb value 1.7×10–9
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