How many moles of Fe3O4 are required to supply enough iron to prepare 0.732 mol Fe2O3?

Question

Question

science chemistry

Answer 1

Answer #1

4 Fe₃O₄ + O₂ --> 6 Fe₂O₃

Fe₃O₄/Fe₂O₃ = 4 : 6

= 2 : 3

= (2/3) : 1

Fe₃O₄ : Fe₂O₃ = (2/3) : 1

= 0.732 * [(2/3) : 1 ]

= (2/3)*0.732 : 0.732

= 0.488 : 0.732

Answer: 0.732 moles Fe₂O₃ are prepared from 0.488 moles Fe₃O₄

Answer 2

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