Question

The following equilibrium reaction is known as the 'water gas shift' reaction: CO(g)+H2O(g)⇔H2(g)+CO2(g) When initially 0.40...

The following equilibrium reaction is known as the 'water gas shift' reaction:
CO(g)+H2O(g)⇔H2(g)+CO2(g)

When initially 0.40 mol of CO(g) and 1.00 mol of H2O(g) are present in a vessel at 1200°C, the pressure is 2 atm. The amount of CO2(g) is 0.225 mol at equilibrium.
a) Calculate the total equilibrium amount, n, of the gas mixture. Hint: Use the ICE table
b) Calculate the extent of dissociation, α.
c) Calculate the number of moles of each gas, except the carbon dioxide gas in the mixture at equilibrium.

I know there is a question like this already posted, but I'm not sure if it is correct. Especially b) because the extent of dissociation was stated to be 0.225 which is the same as the amount of CO2(g) at equilibrium.

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