I am confused on this problem, can someone explain it step by step please. Thank you...

Question

Question

I am confused on this problem, can someone explain it step by step please. Thank you in advance.

One drop (.05 ml) of .10 M kbr is added to 250 ml of a saturated solution of AgCl. (AgBr ksp =5.0 X 10^-13).

science chemistry

Answer 1

Answer #1

equilibrium process is for saturated solution of AgCl:

AgCl (s)<...................> Ag+ (aq) + Cl- (aq)

Ksp of AgBr = 5.0 X 10^-13

and

Ksp of AgCl = 1.8 * 10^-10

As Ksp of AgBr is less than that of AgCl and so the solubility of AgBr is less than that of AgCl.

So

when we add KBr then AgBr precipitated that is above equilibrium shift towards right direction.

thus

In presence of KBr, AgCl is dissolved and formation AgBr precipitate obtained.

Answer 2

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