Question

The table below shows the frequency of outcomes when two distinguishable coins are tossed 4,000 times and the uppermost faces were observed. What is the estimated probability that the second coin lands with tails up? Outcome HH HT TH TT Frequency 1200 1200 600 1000 Round your answer to four decimal places, if necessary.

Answer 1

Table:

Outcome	HH	HT	TH	TT	Total
Frequency	1200	1200	600	1000	4000
Probability	1200/4000 = 0.30	=1200/4000 = 0.30	=600/4000 = 0.15	=1000/4000= 0.25	Total = 1

Numer of outcomes of second coin lands with tails = 1200 + 1000 = 2200

Therefore,

Probability that the second coin land with tails up = 2200 / 4000 = 0.5500

OR 0.30 + 0.25 = 0.5500