The normal boiling point of methanol is 64.7°C. A solution containing a nonvolatile solute dissolved in methanol has a vapor pressure of 717.0 torr at 64.7°C. What is the mole fraction of methanol in this solution?
When a non - volatile solute is added to a solvent then by help of colligative property i.e relative lowering in vapor pressure we can obtain the mole fraction of solvent i.e methanol.
As ( Ps -- P°a )/P°a = mole fraction of solute
So, mole fraction of solute ( chi) = 760 -- 717/760 = 0.056
So mole fraction of methanol is = 1 -- 0.056 = 0.944
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