Suppose a population is known to be normally distributed with a mean, μ, equal to 144 and a standard deviation, σ, equal to 27. Approximately what percent of the population would be between 144 and 171?
Solution :
Given that ,
mean =
= 144
standard deviation =
=27
P(144< x <171 ) = P[(144-144) / 27< (x -
) /
< (171 -144) /27 )]
= P( 0< Z < 1)
= P(Z < 1) - P(Z < 0)
Using z table
= 0.8413-0.1587
=0.6826
=68.26%
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