Suppose a 500.mL flask is filled with 1.7mol of I2 and 0.80mol of HI.
The following reaction becomes possible: H2(g)+I2(g) > 2HI(g).
The equilibrium constant K for this reaction is 0.142 at the temperature of the flask.
Calculate the equilibrium molarity of HI. Round your answer to two decimal places.

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Suppose a 500.mL flask is filled with 1.7mol of I2 and 0.80mol of HI. The following...
Suppose a 250.mL flask is filled with 1.9mol of H2 and 1.7mol of
I2. The following reaction becomes possible:
H2(g) + I2(g) 2HI(g)
The equilibrium constant K for this reaction is 5.99 at the
temperature of the flask.
Calculate the equilibrium molarity of H2. Round your answer to
two decimal places.
Suppose a 500. mL flask is filled with 0.50 mol of H, and 1.7 mol of 12. The following reaction becomes possible: H2(g) +12(g) = 2HI(g) The equilibrium constant K for this reaction is 3.30 at the temperature of the flask. Calculate the equilibrium molarity of HI. Round your answer to two decimal places. xs ?
Suppose a 250.mL flask is filled with 1.1mol of I2 and 0.20mol of HI. The following reaction becomes possible: +H2gI2g 2HIg The equilibrium constant K for this reaction is 0.101 at the temperature of the flask. Calculate the equilibrium molarity of HI. Round your answer to two decimal places.
Suppose a 500. mL flask is filled with 0.50 mol of H2 and 1.9 mol of HI. The following reaction becomes possible: H2(g)+12g2HIg The equilibrium constant K for this reaction is 4.94 at the temperature of the flask. Calculate the equilibrium molarity of H2. Round your answer to two decimal places.
Suppose a 500. mL flask is filled with 0.70 mol of H2 and 0.60 mol of HI. The following reaction becomes possible: -2H1(g) The equilibrium constant K for this reaction is 2.38 at the temperature of the flask. Calculate the equilibrium molarity of H2. Round your answer to two decimal places.
Suppose a 500 mL. flask is filled with 1.9 mol of H, and 0 90 mol of HI. The following reaction becomes possible: H(8)+128)2HI) The equilibrium constant K for this reaction is 0.752 at the temperature of the flask. Calculate the equilibrium molarity of HI. Round your answer to two decimal places.
Suppose a 250 ml flask is filled with 0.30 mol of I, and 1.5 mol of HI. The following reaction becomes possible: H2(g) +12(g)=2HI(g) The equilibrium constant K for this reaction is 0.532 at the temperature of the flask. Calculate the equilibrium molarity of 12. Round your answer to two decimal places. Пм x s ?
Suppose a 500. mL flask is filled with 1.3 mol of H2 and 0.10 mol of HC1. The following reaction becomes possible: H2(g) + Cl2(g)-2HCl (g) The equilibrium constant K for this reaction is 3.03 at the temperature of the flask. Calculate the equilibrium molarity of H2. Round your answer to two decimal places.
Suppose a 500.mL flask is filled with 0.50mol of H2 and 0.70mol of HCl. The following reaction becomes possible: H2g+Cl2g -> 2HClg The equilibrium constant K for this reaction is 1.17 at the temperature of the flask. Calculate the equilibrium molarity of H2. Round your answer to two decimal places.
Suppose a 500.mL flask is filled with 0.60mol of H2 and 0.70mol
of Cl2. The following reaction becomes possible:
H2(g) + Cl2(g) 2HCl(g)
The equilibrium constant K for this reaction is 5.52 at the
temperature of the flask.
Calculate the equilibrium molarity of Cl2. Round your answer to
two decimal places.