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At what positions is the speed of a simple harmonic oscillator one-fourth its maximum? That is,...

At what positions is the speed of a simple harmonic oscillator one-fourth its maximum? That is, what values of x/A give v = ±vmax/2, where A is the amplitude of the motion?


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Answer #1

We know that in SHM velocity of particle at any time is given as:

So, velocity will be max at x=0

Therefore, positions where the speed of SHM is one fourth of maximum will be :

To find the value of X/A when v=vmax /2

We know:

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