The velocity of an enzyme is 20% Vmax. What is the ratio of [S] to KM...

Question

Question

The velocity of an enzyme is 20% Vmax. What is the ratio of [S] to K_M under this condition?

science chemistry

Answer 1

Answer #1

since v is 20% of Vmax assume V_max=1, therefore v= 20/100 * 1 = 0.20

We have the relation

1/v = K_m/V_max x 1/[S] + 1/V_max
1/0.20 = K_m/1 x 1/[S] + 1/1
5 - 1 = K_m/[S]
4 = Km/[S]

1/4 = 0.25 = [S] / K_m

Answer 2

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