Question

My main issue is with "#define IVAR 100" If the result is an integer value write...

My main issue is with "#define IVAR 100"

  • If the result is an integer value write the integer without commas or decimals
  • If the result is a double value write the decimal to exactly 2 decimal places
  • If the operation is division or module and the denominator is zero, write: Invalid
  • If the operation is division or modulo and the denominator is a negative value, write: Varies
  • If the operation is module and the numerator is a negative value, write: Varies

#define IVAR 100

double x, y;

int a, b, i;

a = 9;

b = 4;

y = 5.0;

Question 1) i = (98 - IVAR) / a;

0 0
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Answer #1

The #define command instructs the compiler to create a constant IVAR and set its value to the integer 100.

So, wherever IVAR is being used, its value will be replaced by 100

Therefore, the expression i=(98-IVAR)/a can be calculated as:

i=(98-100)/9

i=-2/9

the result of rhs is -.222, but since i is an integer, it will disregard the fractional part, and will store 0

Hence, the value of i=0

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