Q=3000-20P, where Q is the number of helicopter flights, demanded daily.
Q =3000-20P
P = 0, Q = 3000
P = 1, Q = 3000 - 20 = 2980
The price increases by $1, the change in quantity demanded = 3000 - 2980 = 20 units.
Q =3000-20P,
When P = 0, Quantity demanded = 3000 units.
The maximum quantity demanded is 3000 units.
Q =3000-20P
Q = 0, Price: 20P = 3000 - Q
P = (3000 - 0)/20 =150
The minimum price the seller must charge in order to sell is $150
P= $125, the quantity demanded: Q =3000-20P
Q = 3000 - 20 (125)
Q = 3000 - 2500
Q = 500 units
The demand function with a price on the vertical axis indicating the intercepts and my answer to part d where the price = $125 and the quantity demanded = 500 units.
Below is the supply function with a price on the vertical axis indicating the minimum selling price. The supply function is P=$125 +0.10Qs, so the minimum selling price is when Qs = 0, P = $125 + 0 = $12
Since parts g and h are not answered, it is assumed the student is looking for answers to parts g and h.
G)
At equilibrium, demand = supply
That is,
3000-20P = 10P- 1250
4250 = 30P
P* = $141.67
Q* = 166.67 units
H)
At P = $100,
Qd = 3000-20(100) = 1000 units
Qs = 10(100) - 1250 = -250
Since Qd > Qs, there is a shortage at this price
Shortage = 1000-(-250) = 1250 units
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Can someone help me solve those three questions? thank you so
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