Question

please code in python 3

arr = ['ae', 'anana', 'lolololol', 'aaaaa', 'inkinka', 'playplay', 'fruit', 'cucumbers']

alpha = ['a', 'e' ]

saved = ['']

using arr and alpha, count how many a,c,e,s dose each element have.

for example,

anana must print out 3

because it have three a

while you are counting, at saved array, you must save top 3 elements that have highest number.

for example,

'ae', 'anana', 'lolololol', 'aaaaa', 'inkinka', 'playplay', 'fruit', 'not']

2 3 0 5 1 2 0 0

since aaaaa, anana have highest and ae and playplay have same number,

saved must have

saved = ['aaaaa', 'anana', 'ae', 'playplay']

Answer 1

Python code to perform the above operation is as follows.

Source code:

arr = ['ae', 'anana', 'lolololol', 'aaaaa', 'inkinka', 'playplay', 'fruit', 'cucumbers'] alpha = ['a', 'e', 'c', 's' ] saved = [] # Counting the characters char_count_dict = {} count = 0 for element in arr:   for char in alpha:     count += element.count(char)   print(count) # Printing the count   char_count_dict[element] = count   count = 0 # saving top three elements that have highest value to saved array for i in range(0,3):   max_value = max(char_count_dict.values())   keys = [key for key,value in char_count_dict.items() if value == max_value]   for key in keys:     saved.append(key)     del char_count_dict[key] print(saved) # Printing saved array

Output:

2 3 0 5 1 2 0 4 ['aaaaa', 'cucumbers', 'anana']

Screenshot of running code and output:

Development Environment : Googlecolab