of performance of an ... An ideal refrigerator does 175.0 J of work to remove 780.0...
of performance of an ... An ideal refrigerator does 175.0 J of work to remove 780.0 J of heat from its cold compartment during each cycle. What is the refrigerator's coefficient of performance? Tries 0/20
How much heat per cycle is exhausted to the kitchen?
Homework Answers
here,
the work done,W = 175 J
the heat removed from the cold chamber during each cycle , Qc = 780 J
the COP = W /Qc
COP= 175 /780
COP = 0.224
the heat exhausted to the kitchen , Qh = W + Qc
Qh = 175 J + 780 J
Qh = 955 J
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