If the scores for a test have a mean of 70 and a standard deviation of 12, find the percentage of scores that will fall below 60.
P( x < 70) = P( z < ___(j)_________) = ______(k)_____________
Here
= 70
= 12
P(x < 60) = P[z < (60 - 70)/12] = P(z < -0.833)
here using the NORMSDIST function or using z table
P(x < 60) = P[z < (60 - 70)/12] = P(z < -0.833) = 0.2023
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