A pure sample of 226Ra contains 2.6 × 1013 atoms of the isotope. If the half-life...
A pure sample of 226Ra contains 2.6 × 1013 atoms of the isotope. If the half-life of 226Ra = 1.6 × 103 years, what is the decay rate of this sample? (1 Ci = 3.7 × 1010 decays/s)
Homework Answers
T1/2 =1.6*10^3 y
=1.6*10^3 y*(365.25 d/1y)*(24h/1d)*(60 min/1h)*(60 sec/1 min)
=5.049216*10^10 sec
decay constant (lamda) =(ln 2)/(T1/2) =1.37278*10^-11 /sec
decay rate =(2.6*10^13 atoms)*1.37278*10^-11 /sec
=356.9228 atoms/sec
decay rate =356.9228 atoms/sec*(1Ci /3.7*10^10 decays/sec)
=9.65*10^-9 Ci
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A pure sample of 226Ra contains 2.6 × 1013 atoms of the isotope.
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