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Application 1 and 2 run concurrently. Whenever a timeout interrupt occurs, the kernel switches control between...

Application 1 and 2 run concurrently. Whenever a timeout interrupt occurs, the kernel switches control between the applications. Show the order of instruction execution, assuming application 1 is currently running. (42 pts)

Application 1

Application 2

...

instruction i

(timeout interrupt)

instruction i+1

...

instruction k

(timeout interrupt)

instruction k+1

...

instruction 0

...

instruction j

(timeout interrupt)

instruction j+1

...
  1. _______
  2. _______
  3. _______
  4. _______
  5. _______
  6. _______
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Answer #1

At the begining Application will keep on executing Application 1 unless timeout interrupt comes. Now it will switch to Application 2. It will continue executing application 2 unless an interrupt occurs.
So, flow will be :
Application 1 (till instruction i)
|
Application 2 ( inst 0 to j)
|
Application 1 ( instruction i+1 till next interrupt)
|
.
.
.
Application i (depending upon the turn or execution time of an Application ) |

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