In a cylinder with a cross-sectional area A = 100 cm2 the air is at a Temperature t1 = 12C. The atmospheric pressure is equal to p1 = 101 kPa. At altitude h1 = 60 cm from the bottom of the cylinder there is an airtight, movable piston. By which distance will the piston sinks, when a weight of m = 100 kg falls on the piston and heats the air in the cylinder up to a temperature t2 = 27C? Neglect the frictional force between the piston and cylinder walls and the mass of the piston.
Thank you so much. A clear explanation is highly appreciated!
The piston sinks by a distance of 28.263 cm .
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