The pH of a 0.0145M perchloric acid solution is:
| A | 7.0 |
| B | 1.84 |
| C | 12.2 |
Perchloric acid is strong acid and dissociates completely.
HClO4 --------> H+ + ClO4-
1 mole HClO4 produce 1 mole H+. (Ratio 1:1).
Therefore, molarity of H+ = HClO4 = 0.0145 M.
Now, pH = - log [H+]
= - log ( 0.0145 )
= 1.838 = 1.84
Ans = B = 1.84.
The pH of a 0.0145M perchloric acid solution is: A 7.0 B 1.84 C 12.2
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