The end of a diving board undergoes simple harmonic motion with the velocity shown below: vy(t)=vmax*sin((2*pi*t)/T)...
The end of a diving board undergoes simple harmonic motion with the velocity shown below: vy(t)=vmax*sin((2*pi*t)/T) where vmax = 4.64 m/s and T = 0.553 seconds. (calculator must be in radians)
What is the angular frequency of the board's velocity?
What is the amplitude of the board's position?
Homework Answers
Velocity is given by:
Vy(t) = Vmax*sin (2*pi*t/T)
Now given that Vmax = 4.64 m/sec
T = time period = 0.553 sec
Part A.
Angular frequency is given by:
w = 2*pi/T
w = 2*pi/0.553
w = 11.36 rad/sec
Part B.
Relation between amplitude and max velocity is given by:
Vmax = A*w
A = Vmax/w
A = 4.64/11.36
A = 0.41 m = Amplitude
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