Suppose that Bob's knapsack private key is (3, 5, 10, 23), multiplier is m-1 = 6,...
Suppose that Bob's knapsack private key is (3, 5, 10, 23), multiplier is m-1 = 6, and modulus n = 47. What is the plaintext (in hex) if the ciphertext C = 20?
Homework Answers
Solution:
given m-1=6 modulus n=47 ciphertext=20 private key ={3,5,10,23}
plaintext= ciphertext 
m-1
mod n. Therefore, 20 6
mod 47= 26
Now we have to find out by adding which keys from the set of private keys can we form 26, the just place 1 for those digits and 0 for others.
we know 23+3=26 therefore 1001. so the plain text is 1001.
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Suppose that Bob's knapsack private key is (3, 5, 10, 23),
multiplier is m-1 = 6,...
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