Question

What is the value for the equilibrium constant for the following reaction: 4HCl (g) + O2 (g) ⇌ 2H2O (l) + 2Cl2 (g) Given the equilibrium concentrations: [HCl] = 0.26 M; [O2] = 0.32 M; [H2O] = 0.65 M; [Cl2] = 0.59 M

Answer 1

Answer - We are given,

Reaction -  

4HCl (g) + O₂ (g) <----> 2H₂O (l) + 2Cl₂ (g)

The equilibrium concentration

[HCl] = 0.26 M;

[O2] = 0.32 M;

[H2O] = 0.65 M;

[Cl2] = 0.59 M

We know the Kc expression for the given reaction is as follows:

Kc = [Cl₂]² / [HCl]⁴ [O₂]

The Kc expression contain only gases and aqueous phase only.

Now plugging the values in the formula.

Kc = (0.59 M)² / (0.26 M)⁴ x (0.32 M)

      = 238

The equilibrium constant for the above reaction is 238.