Question

How many grams of co2 are produced from the combustion of 10.0 g of methanol CH3OH?

Answer 1

The balanced equation for the combustion of methanol is as follows

2CH3OH (l) + 3O2(g) → 2CO2 (g) + 4H2O (l)

CH3OH mol. Wt = 32

CO2 mol. Wt = 44

Here, two moles of methanol undergo oxidation to form two moles of CO2 (Thus it is in 1:1 ratio)

32 gm of methanol gives 44 gm of CO2

thus 10 gm of methanol will give x gm of CO2

amount of CO2 formed = (10*44)/32 = 13.75 gm of CO2