Use the normal distribution of heights of adult women, which has a mean of 166 centimeters and a standard deviation of 6
centimeters, and the following table with the standard scores and percentiles for a normal distribution to find the indicated quantity.
The percentage of heights between 163 centimeters and 169 centimeters is ______%.
| Full data set | |||
|
Standard score |
% |
Standard score |
% |
|---|---|---|---|
|
minus−3.0 |
0.13 |
0.1 |
53.98 |
|
minus−2.5 |
0.62 |
0.5 |
69.15 |
|
minus−2 |
2.28 |
0.9 |
81.59 |
|
minus−1.5 |
6.68 |
1 |
84.13 |
|
minus−1 |
15.87 |
1.5 |
93.32 |
|
minus−0.9 |
18.41 |
2 |
97.72 |
|
minus−0.5 |
30.85 |
2.5 |
99.38 |
|
minus−0.1 |
46.02 |
3 |
99.87 |
|
0 |
50.00 |
3.5 |
99.98 |
Given that, mean (μ) = 166 centimetres and
standard deviation
= 6 centimetres
We want to find, P(163 < X < 169)

Therefore, the percentage of heights between 163 centimeters and 169 centimeters is 38.30%
Use the normal distribution of heights of adult women, which has a mean of 166 centimeters...
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