V = 50 cos (40 ω t + 30) + 28.2 cos (40 ω t + 30) R = 5 find P?
a.1125
b.650
c.330
d.550
r(t) = 10 sin(300t + 60°) cos(x - 90) sin(x) v(t) 10 cos(300t- 30°) ω = 300, Mag = 10, θ =-30° v 102-30 MLP Mcos(P) +jMsin(P) v = 10 cos(-30) +j10 sin(-30) Step 1: Convert to Cosine Step 2: Identify Frequency, Magnitude, and Phase Step 3: Convert to real/imag form = 8.66-J5 Step 4: Solve Step 5: Convert Back
rrent 1 for R 40 Ω and R1-30 Ω for: No. 4 R1 30 V 6Ω R1 50 V 6Ω se Δ to Y transformation.
For the circuit shown below. Ifv.(t) = 100 cos(2001+30) V and vy(t) = 50 cos(2000) V. a) Redraw the circuit using Phasor equivalent. b) In the Phasor domain, find the node voltage equations. 1 mF 20 ml 30 000 30 mH 0.25 mF
Please explain!
12. In the circuit shown, R,-4.00 Ω,R,-7.00 Ω, C-25.0 μF, and V,-(21.4 V)Cos[(5756 rad/s)t]. what is the nominal value of the inductor that can be added in series with the source that wll make the power factor 1 A) 604 HH B) 606 μΗ C) 608 μΗ D) 610 μΗ E) None of these R2
12. In the circuit shown, R,-4.00 Ω,R,-7.00 Ω, C-25.0 μF, and V,-(21.4 V)Cos[(5756 rad/s)t]. what is the nominal value of the inductor that...
For the circuit above, vS(t) = 120
cos(20t+45°) V, R = 100 Ω, L = 5 H,
C = 5 mF.
Find vO(t).
www. visco) 1 c+vol)
Find io using superposition
20 μF 50 cos 2 000t V +) $ 80 Ω $ 100 Ω 40 mH δο 2 sen 4 000t A ξ 60 Ω (+) 24V
2.ท. V. 2 R V10 cos (10ot) v] Vi V10 cos (50 t) Ev] FiND )
Given v(t) = 60cos(wt - 10) V and i(t) = 1.5 cos(wt +50)A find a. Complex Power (S) (2 pts.) b. Apparent Power (SI)(1 pts.) C. Real Power (P) (1 pts.) d. Power factor (2 pts.) e. Reactive Power (Q) (1 pts.) f. Impedance (Z) (1 pts.) g. Capacitance (C) ((2 pts.)
1) A buck chopper like that in Figure I has the following data 250 μΗ, D E 40 V, T Find: 50 μ. L 0.4, C-60 μF, and R 10 Ω. ) the value of L necessary for the continuous current mode (b) Vc (c) Imax and Imin (d) Av r like that in Figure 1 requires an output power of 100 at an output voltage of 24 V from a 60-V supply. The switching fre- quency is 60 kHz....
Rs ) i2(t) s(t) Ideal FIGURE P15-12 15-13 In Figure P15-12 Rs-50 Ω, R.-20, the turns ratio is n= 1/5, and the source voltage is vs (1) = 440 cos 4001 V. Find expressions for vi (t) and v2(). Validate your answer using Multisim.