A person of average density of 980 kg/m3 floats in seawater of density 1025 kg/m3. What...
A person of average density of 980 kg/m3 floats in seawater of density 1025 kg/m3. What can you determine using this information? Determine everything.
Homework Answers
D = 1025kg/m^2
d = 980kg/m^2
Let height of person submerged in water is h
And H be the total height of person.
Hence h/H = 980/1025 = 0.956
=) h = (0.956)H
That means 95.6% of person height is inside seawater.
And 100-95.6 = 4.4% is out from seawater because seawater is more denser than person .
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