If an aqueous solution is 5.08 % by weight in sodium chloride and contains 1.79 g of sodium chloride, what mass of water is present in the solution?
Weight %age of solution = 5.08%
Weight of the solute (NaCl) given = 1.79g
Weight of solvent ( water) = ?
And weight %age of solution is calculated as,
Wt % of soln = (mass of solute × 100) / mass of solution
5.08 = (1.79g÷ mass of solution) × 100
Mass of solution =( 1.79 g ×100)/5.08
= 35.24 g
Mass of solvent = mass of solution - mass of solute
= 35.24g - 1.79g
= 33.45g
So, mass of water in solution = 33.45g
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